Buffer Index /spec/d4dff54
run=1 · site=sys-log-llki.cloud · 2026-10-27 01:07Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-t²) dt = √π / 2
278K
2H₂O₂ → 2H₂O + O₂
4Fe + 3O₂ → 2Fe₂O₃
det| 3 5 ; 4 4 | = -8
47K
det| 12 3 ; 7 13 | = 135
∑_{k=1}^{n} k = n(n+1)/2
480K